Integration of a natural log and polynomial

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SUMMARY

The discussion focuses on evaluating the indefinite integral of ln(x² + 19x + 84) dx for x > 0. The initial approach involved integration by parts, where u = ln(x² + 19x + 84) and dv = dx. However, the user found their solution incorrect and received advice to factor the quadratic expression, leading to a simpler integration method. Ultimately, the suggested method proved effective and significantly easier than the original approach.

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  • Familiarity with logarithmic functions and their properties.
  • Knowledge of polynomial factoring and simplification.
  • Basic calculus concepts, including indefinite integrals.
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  • Study integration by parts in detail, focusing on the formula integral of u*dv = uv - integral of (du*v).
  • Learn polynomial factoring techniques to simplify integrals involving logarithmic functions.
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Homework Statement



Evaluate the integral when x > 0:

indefinite integral of ln(x2+19x+84)dx

Homework Equations



I know I need to use some form of integration by parts: integral of u*dv=uv-(integral of(du*v))

The Attempt at a Solution



I began by making u=ln(x2+19x+84) and dv=dx. Thus, (after u-substitution) du=(2x+19)/(x2+19x+84) and v=x.

After putting that in the formula, we get x*ln(x2+19x+84)-(integral of)((2x2+19x)/(x2+19x+84)). After simplifying that, I get:

x*ln(x2+19x+84)-((x2+19x+84)(4x+19)-(2x2+19x)(2x+19))/((x2+19x+84)2)

But according to the program I am using, that is the incorrect answer. Do you have any suggestions? Thanks.
 
Last edited:
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Why not just factor the quadratic, then split up the integral into two simpler log terms then use:

\int ln(u)du=u\ln(u)-u
 
Hmm, by infinite do you mean definite integral from 0 to infinity? If so, it's clearly divergent.
 
No, sorry, I meant the indefinite integral.
 
Thanks Jackmell. I tried that method and it worked. (A lot easier than the method I was using.)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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