- #1

- 24

- 0

Worked out the problem. Got

X^2+2x-1=A(2x-1)(x+2)+bx(x+2)+cx(2x-1)

Ok then you write it standard form for a polynomial. Then use can use there coefficients to write new equations at you get

2a+b+c=1

3a+2b-c=2 and finally

-2a=1

Now you solve for a,b,c and this is where I'm confused.

To solve for a is easy, it is just 1/2. But the book doesn't show how to solve for b and c.

B =1/5 and C =-1/10

I'm totally confused how they got those numbers so if you could explain it. That would be so helpful!!