Ok all save y'all a little reading. Worked out the problem. Got X^2+2x-1=A(2x-1)(x+2)+bx(x+2)+cx(2x-1) Ok then you write it standard form for a polynomial. Then use can use there coefficients to write new equations at you get 2a+b+c=1 3a+2b-c=2 and finally -2a=1 Now you solve for a,b,c and this is where I'm confused. To solve for a is easy, it is just 1/2. But the book doesn't show how to solve for b and c. B =1/5 and C =-1/10 I'm totally confused how they got those numbers so if you could explain it. That would be so helpful!!