Integration over a set in n-dimensional space

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The discussion focuses on evaluating the integral Q(C) over a specific set C in n-dimensional space, where the bounds are defined by the inequalities 0 ≤ x1 ≤ x2 ≤ ... ≤ xn ≤ 1. The integral evaluates to 1/n!, which is a point of confusion for some participants. A suggestion is made to approach the problem by solving a more general integral I_n(x) using induction, starting with the base case I_1(x) = x. Participants are encouraged to compute I_n(x) for small values of n to identify a pattern and confirm it through induction. Understanding this approach is essential for correctly deriving the result of 1/n!.
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Homework Statement
Not a homework problem, but self-studying Example 1.2.24 from Hogg et al.'s Introduction to Mathematical Statistics (7th ed).
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Example 1.2.24: Let C be a set in n-dimensional space, and let Q(C) = ∫...∫Cdx1dx2...dxn. If C= {(x1,x2,...,xn : 0 ≤ x1 x2 ≤ ... ≤ xn ≤ 1}, then Q(C) = ∫010xn0xn-1...∫0x30x2dx1dx2...dxn = 1/n!. (Apologies for the poor formatting of the integration bounds.)

I haven't the foggiest idea how to get to 1/n!. My solution for the latter integral is x2x3...xn. Even if I were to assume that [0, 1] were divided into intervals of equal length, giving x1 = 1/n, x2 = 2/n, etc., I get n!/nn, which I'm pretty sure doesn't reduce to 1/n!. My assumption is that I am somehow integrating the second integral incorrectly, but I'm not sure how. Any suggestions would be appreciated!
 
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I suggest you start by solving the more general integral
$$
I_n(x) = \int_0^{x} \int_0^{x_{n}} \cdot \int_0^{x_2} dx_1\, dx_2\ldots dx_{n}.
$$
You can solve this by induction. The base case is $$I_1(x) = \int_0^x dx_1 = x$$.

Compute the integral ##I_n(x)## for the first few values of ##n## and try to see the pattern. Then show that it is the correct pattern by induction applying$$I_{n+1}(x) = \int_0^x I_n(x_{n+1}) dx_{n+1}$$
 
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First, I tried to show that ##f_n## converges uniformly on ##[0,2\pi]##, which is true since ##f_n \rightarrow 0## for ##n \rightarrow \infty## and ##\sigma_n=\mathrm{sup}\left| \frac{\sin\left(\frac{n^2}{n+\frac 15}x\right)}{n^{x^2-3x+3}} \right| \leq \frac{1}{|n^{x^2-3x+3}|} \leq \frac{1}{n^{\frac 34}}\rightarrow 0##. I can't use neither Leibnitz's test nor Abel's test. For Dirichlet's test I would need to show, that ##\sin\left(\frac{n^2}{n+\frac 15}x \right)## has partialy bounded sums...