Integration-problem using u-substitution

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The integral ∫(ex)/(2ex+2)dx can be approached using u-substitution with u=2ex+2, leading to the expression ∫(1)/(2u)du, which simplifies to 1/2ln|u| + c. However, this method results in the answer 1/2ln|2ex+2|, while the correct answer is 1/2ln|ex+1|. The discrepancy arises because both forms are valid; they differ only by a constant factor. To reconcile the two answers, recognize that 2ex+2 can be expressed as a constant multiple of ex+1, allowing the logarithmic properties to yield the same result. Ultimately, both approaches are correct, emphasizing the importance of constants in integration.
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Homework Statement



∫(ex)/(2ex+2)dx

Homework Equations



and I am told to use:

u=2ex+2

The Attempt at a Solution



If i use u=2ex+2 as the task says;

du/dx = 2ex and dx =du/2ex

∫(ex)/(u)du/2ex=∫(1)/(2u)du=1/2ln|u| + c =1/2ln|2ex+2|

according to the book the answer should be 1/2ln|ex+1|

however if i use u =ex+1 and write the integral 1/2∫(ex)/(ex+1)dx i get the correct answer. Where am i going wrong?
 
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they are both correct, the only difference is the constant of integration, which you don't know anyway. Hint: write 2ex+2 as a constant times ex+1, and then make use of the properties of logarithms to see that you get the same answer (without caring about the constant of integration, since you don't know it anyway).
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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