Integration-problem using u-substitution

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SUMMARY

The integral ∫(ex)/(2ex+2)dx can be solved using the substitution u=2ex+2. The derivative du/dx equals 2ex, leading to dx=du/2ex. This results in the integral transforming to ∫(1)/(2u)du, yielding 1/2ln|u| + c. However, an alternative substitution of u=ex+1 produces the correct answer of 1/2ln|ex+1|, highlighting the importance of recognizing equivalent forms in logarithmic expressions.

PREREQUISITES
  • Understanding of integration techniques, specifically u-substitution.
  • Familiarity with logarithmic properties and their applications in calculus.
  • Knowledge of differentiation and how to compute derivatives.
  • Basic algebra skills for manipulating expressions.
NEXT STEPS
  • Study advanced u-substitution techniques in integral calculus.
  • Learn about properties of logarithms and their implications in integration.
  • Explore alternative methods for solving integrals, such as integration by parts.
  • Practice solving integrals with varying substitutions to reinforce understanding.
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Students studying calculus, particularly those focusing on integration techniques, as well as educators looking for clarification on common substitution errors in integrals.

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Homework Statement



∫(ex)/(2ex+2)dx

Homework Equations



and I am told to use:

u=2ex+2

The Attempt at a Solution



If i use u=2ex+2 as the task says;

du/dx = 2ex and dx =du/2ex

∫(ex)/(u)du/2ex=∫(1)/(2u)du=1/2ln|u| + c =1/2ln|2ex+2|

according to the book the answer should be 1/2ln|ex+1|

however if i use u =ex+1 and write the integral 1/2∫(ex)/(ex+1)dx i get the correct answer. Where am i going wrong?
 
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they are both correct, the only difference is the constant of integration, which you don't know anyway. Hint: write 2ex+2 as a constant times ex+1, and then make use of the properties of logarithms to see that you get the same answer (without caring about the constant of integration, since you don't know it anyway).
 

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