and im told to use:
The Attempt at a Solution
If i use u=2ex+2 as the task says;
du/dx = 2ex and dx =du/2ex
∫(ex)/(u)du/2ex=∫(1)/(2u)du=1/2ln|u| + c =1/2ln|2ex+2|
according to the book the answer should be 1/2ln|ex+1|
however if i use u =ex+1 and write the integral 1/2∫(ex)/(ex+1)dx i get the correct answer. Where am i going wrong?