Integration-problem using u-substitution

  • Thread starter johann1301
  • Start date
  • #1
217
1

Homework Statement



∫(ex)/(2ex+2)dx

Homework Equations



and I am told to use:

u=2ex+2

The Attempt at a Solution



If i use u=2ex+2 as the task says;

du/dx = 2ex and dx =du/2ex

∫(ex)/(u)du/2ex=∫(1)/(2u)du=1/2ln|u| + c =1/2ln|2ex+2|

according to the book the answer should be 1/2ln|ex+1|

however if i use u =ex+1 and write the integral 1/2∫(ex)/(ex+1)dx i get the correct answer. Where am i going wrong?
 
Last edited:
  • #2
they are both correct, the only difference is the constant of integration, which you don't know anyway. Hint: write 2ex+2 as a constant times ex+1, and then make use of the properties of logarithms to see that you get the same answer (without caring about the constant of integration, since you don't know it anyway).
 

Suggested for: Integration-problem using u-substitution

Replies
12
Views
752
Replies
11
Views
810
Replies
12
Views
1K
Replies
3
Views
631
Replies
4
Views
342
Replies
4
Views
787
Replies
3
Views
473
Back
Top