Integration using inverse trig indentities?

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Cpt Qwark
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Homework Statement


1.[tex]\int{\frac{sinx}{1+cos^{2}x}} \, dx[/tex]
2.[tex]\int{\frac{1}{13-4x+x^2}} \, dx[/tex]

Homework Equations


Inverse trig identities.

The Attempt at a Solution


For the first one, I'm not too sure about what to do with the [tex]sinx[/tex] on the numerator and i have tried u-substitution to no avail (different answer). For the second one, I tried factorising but only had solutions for [tex]x\inℂ[/tex].
 
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You can maybe try to start with the substitution u = cos(x) and reforming the integral. A second substitution will be necessary after the first substitution.
 
eple said:
You can maybe try to start with the substitution u = cos(x) and reforming the integral. A second substitution will be necessary after the first substitution.
Second substitution is not necessary. It can be done in that first one.