Integration where am I going wrong?

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The discussion revolves around a math problem involving the integration of the function v = 200sin(100pi*t + 0.2) and the evaluation of its integral between specific limits. The user initially calculated the integral correctly but encountered discrepancies when applying the limits, leading to an incorrect result of 344 instead of the expected 124.8. The error was identified as a miscalculation in dividing by 200pi, where parentheses were not used appropriately on the calculator. Once the user corrected this mistake, they were able to resolve the issue and understand the importance of proper notation in calculations.
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Hi,
I have an example in my studies as follows:
If v = 200sin(100pi*t + 0.2) then evaluate Integral of v^2 dt between limits of 0.005 and 0.

I have integrated it and used the double compound angle formula sin^2 A=1-cos2A and come up with the following as per the solution to the example in the home work studies:
20000 [t - (sin(200pi*t + 0.4)/200pi) ] ... so far so good I think.

However when I put the limits in it I get

20000 [0.005 - (sin(200pi*0.005 + 0.4)/200pi)) - (0 - (sin(200pi*0 + 0.4)/200pi)) ]

This I calculate as 20000 (0.005 + 0.0061) - (0 -0.0061) = 344

According to the solution and online examples the answer should be 124.8

The solution with the limits calculated shows 20000 [ (0.005+0.00062) - (0 - 0.00062)] but I can't get these figures from what I have above. Please can anyone see where I am going wrong? It is driving me mad!
 
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fuofa said:
Hi,
I have an example in my studies as follows:
If v = 200sin(100pi*t + 0.2) then evaluate Integral of v^2 dt between limits of 0.005 and 0.

I have integrated it and used the double compound angle formula sin^2 A=1-cos2A and come up with the following as per the solution to the example in the home work studies:
20000 [t - (sin(200pi*t + 0.4)/200pi) ] ... so far so good I think.

However when I put the limits in it I get

20000 [0.005 - (sin(200pi*0.005 + 0.4)/200pi)) - (0 - (sin(200pi*0 + 0.4)/200pi)) ]

This I calculate as 20000 (0.005 + 0.0061) - (0 -0.0061) = 344

According to the solution and online examples the answer should be 124.8

The solution with the limits calculated shows 20000 [ (0.005+0.00062) - (0 - 0.00062)] but I can't get these figures from what I have above. Please can anyone see where I am going wrong? It is driving me mad!
You miss a term in ##20000 [t - (\sin(200\pi t + 0.4)/200\pi) ]##
Carefully redo the integral.
Post your full calculation, so that we can help finding a possible error.
 
Hi Thank you very much for your reply.

I have just twigged my error in my calculation - I've literally been at it 3 hours!

I don't believe I have missed a term the error was when dividing by 200pi on the calculator. I was dividing [sin(200pi(0.005)+0.4)] by 200pi not by (200pi).

Glad that is sorted now it was giving me a real head ache and I thought dividing the sum by 200 (pi symbol) on the calculator would work fine, but it appears i needed to divide the sum by [200(pi symbol)]

Thanks again.
 
If you enter, on your calculator , "A/B*C" the calculator will interpret that as (A/B)*C. If you want A/(BC) you need to use parentheses.
 
That's indeed how I was going wrong. Thanks for the clarification on how it works. It confirmed my suspicions.
 
There are probably loads of proofs of this online, but I do not want to cheat. Here is my attempt: Convexity says that $$f(\lambda a + (1-\lambda)b) \leq \lambda f(a) + (1-\lambda) f(b)$$ $$f(b + \lambda(a-b)) \leq f(b) + \lambda (f(a) - f(b))$$ We know from the intermediate value theorem that there exists a ##c \in (b,a)## such that $$\frac{f(a) - f(b)}{a-b} = f'(c).$$ Hence $$f(b + \lambda(a-b)) \leq f(b) + \lambda (a - b) f'(c))$$ $$\frac{f(b + \lambda(a-b)) - f(b)}{\lambda(a-b)}...

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