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Integration with sqrt in denominator

  1. Mar 29, 2012 #1
    I wonder how would I get out the integral when the denominator is square-rooted.

    ∫[itex]\frac{1}{\sqrt{3x-x^2}}[/itex] dx
     
  2. jcsd
  3. Mar 29, 2012 #2
  4. Mar 29, 2012 #3
    3x-x² = (3/2)²-(x -(3/2) )²
    Let (x -(3/2) )= (3/2)*sin(t)
    or let (x -(3/2) )= (3/2)*sinh(t)
     
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