Integration with sqrt in denominator

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senorarosada
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I wonder how would I get out the integral when the denominator is square-rooted.

∫[itex]\frac{1}{\sqrt{3x-x^2}}[/itex] dx
 
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3x-x² = (3/2)²-(x -(3/2) )²
Let (x -(3/2) )= (3/2)*sin(t)
or let (x -(3/2) )= (3/2)*sinh(t)