Interference of Sound Waves in a Circular Tube

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A sound wave with a frequency of 2300 Hz is introduced into a circular tube, creating interference patterns at a receiver located at an angle of 130° from the source. The discussion revolves around calculating the level of interference at the receiver and how it changes with frequency adjustments to 230 Hz and 23 Hz. The calculations involve determining the circumference of the tube and assessing the relationship between wavelength and the resulting interference, with an emphasis on constructive versus destructive interference. Participants express urgency for assistance due to an upcoming exam, highlighting the importance of understanding sound wave behavior in different mediums. The conversation underscores the significance of frequency and wavelength in sound wave interference.
JeanDucreaux
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1. A sound wave with frequency f = 2300Hz is sent into a circular tube of radius R=160cm through an opening at some point A.
A receiver lies at point B, separated from A by an angle α=130°. The speed of sound in air is v=330 m/s.
Sound propagates from A to B in both directions along the tube.
(a) What level of interference do you observe at B?
(b) What happens if the frequency is lowered to f1=230 Hz?
(c) And to f2= 23Hz?

2. I guess, I have to calculate the periphery of the circle with given R, and hence divide Δx with λ, which would give me n. If its closer to a whole number, it would result in a constructive interference. With questions (b) and (c), my guess is, that it does not change the level of interference, since 230 and 23 are multiple integers of 2300 (factor 10).
 
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Hello Jean, and welcome to PF.

Well, what do you find under (a)? What's against showing your results ?
And for (b) and (c) I wouldn't guess, but either see that yes, it is as you suspect, or no, factors of 10 can make a considerable difference!
 
can u guys help me pls?
i got an exam tomorrov and I really need your help!
When the sound goes from surface to another(for example from water to air) what satys the same
a)period b)amplituda c) elongacioni d) frekuenc
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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