- #1

SpiderET

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Probably the most famous experiment confirming GR is bending of light by Sun. Here are the best explanations to this topic what I have found:

http://www.mathpages.com/rr/s8-09/8-09.htm

http://mathpages.com/rr/s6-03/6-03.htm

Especially the graph of GR double bending vs Newtonian bending is interesting and the text under it (have bolded part of it):

According to the calculation of 1911, the rate of deflection is a maximum at the point of closest approach to the gravitating body (i.e., where x = 0 and y = R), and the calculation of 1915 gives the same rate of deflection at that point. However, the 1915 calculation,

So here comes my question: If I understand it right, there is no "fixed" curvature caused by Sun, which is causing this double deflection compared to Newtonian deflection value, but it is a function of spatial curvature and time dilation and it is heavily depending on the speed of the particle.

An example of my understanding (please correct me if I am wrong):

If we have photon bended by Sun, we have double bending compared to Newtonian calculation. If we would have an low invariant mass neutrino with speed 99,9999% of c, then we would still have nearly double bending compared to Newtonian calculation. But if we would have a neutrino with 50% of c, then the bending would be almost the same as in Newtonian calculation.

http://www.mathpages.com/rr/s8-09/8-09.htm

http://mathpages.com/rr/s6-03/6-03.htm

Especially the graph of GR double bending vs Newtonian bending is interesting and the text under it (have bolded part of it):

According to the calculation of 1911, the rate of deflection is a maximum at the point of closest approach to the gravitating body (i.e., where x = 0 and y = R), and the calculation of 1915 gives the same rate of deflection at that point. However, the 1915 calculation,

**accounting for the spatial as well as temporal curvature**, shows that there are actually two points of maximum rate of deflection, at the locations x = ±R/2. The integrated area under the 1911 curve is 2, whereas the integrated area under the 1915 curve is 4, but this plot shows that the relationship between the two is not as simple as one might think based on the fact that the latter happens to give twice the total deflection of the former (to the first order in m/r in the small-deflection limit).So here comes my question: If I understand it right, there is no "fixed" curvature caused by Sun, which is causing this double deflection compared to Newtonian deflection value, but it is a function of spatial curvature and time dilation and it is heavily depending on the speed of the particle.

An example of my understanding (please correct me if I am wrong):

If we have photon bended by Sun, we have double bending compared to Newtonian calculation. If we would have an low invariant mass neutrino with speed 99,9999% of c, then we would still have nearly double bending compared to Newtonian calculation. But if we would have a neutrino with 50% of c, then the bending would be almost the same as in Newtonian calculation.

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