Maximizing Golf Ball Distance and Hole in One: Intro Physics HW Help

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A golfer hits a ball at a speed of 27.0 m/s, and the discussion focuses on calculating the time the ball spends in the air and the maximum distance for a hole-in-one. The optimal launch angle for maximum distance in projectile motion is identified as 45 degrees. Participants suggest using kinematic equations to derive the time of flight and range, emphasizing the relationship between vertical and horizontal components of velocity. The range can be calculated using the formula R = Vx * T, where Vx is the horizontal velocity and T is the time in the air. Clear solutions to the problems are sought for better understanding.
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hey everyone, i have a few questions that i just don't understand.
1) a golfer imparts a speed of 27.0m/s to a ball, it travels the max possible distance b4 landing on the green. the tee and the green are at the same level. a) how much time does the ball spend in the air? b) wat is the longest "hole in one" that the golfer can make, if the ball does not roll when it hits the ground?


i would really really appreciate ur help and if someone can do these problems can u please give clear solutions?
thanx alot
 
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I believe 45 degrees is the angle that produces the longest distance in projectile motion.
 
a)
y = y_0 + v_{0y}t + \frac{1}{2}a_yt^2
x = x_0 + v_{0x}t + \frac{1}{2}a_xt^2
Both equations (especially the latter) reduce quite nicely with some logical thinking (what sort of velocity has an effect on the time?). Then just put the equations together and find the maximum (hint: derivate). Quickly done: 45 degrees does look like the correct answer. Now just throw the angle into the (reduced) equation you got in the first step.
Hint: Express v_0 in v_{0y} and v_{0x}

b) You already got the equation you need in a). Now just throw the velocity in and you're done.
 
Last edited:
Päällikkö said:
a)
y = y_0 + v_{0y}t + \frac{1}{2}a_yt^2
x = x_0 + v_{0x}t + \frac{1}{2}a_xt^2
Both equations (especially the latter) reduce quite nicely with some logical thinking (what sort of velocity has an effect on the time?). Then just put the equations together and find the maximum (hint: derivate). Quickly done: 45 degrees does look like the correct answer. Now just throw the angle into the (reduced) equation you got in the first step.
Hint: Express v_0 in v_{0y} and v_{0x}

b) You already got the equation you need in a). Now just throw the velocity in and you're done.

thanks that also just helped me
 
but i simply used the equation for range to find longest
distance which is same as X, R=X= Vox*T,
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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