Intro to Differential Equations Problem #1

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Homework Help Overview

The discussion revolves around finding the general solution to a second-order linear homogeneous differential equation, specifically y'' - 5y' + 6y = 0.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore factorization of the characteristic equation m^2 - 5m + 6 = 0, with some suggesting different approaches to solving it. There are attempts to verify the correctness of the factorization and the proposed solutions.

Discussion Status

The discussion includes various interpretations of the factorization process, with some participants questioning the accuracy of previous attempts. There is a suggestion to check the validity of the proposed solutions, indicating a productive direction in the exploration of the problem.

Contextual Notes

Some participants express uncertainty about the factorization of the characteristic equation, leading to differing proposed solutions. There is a lack of consensus on the correct approach to the problem.

JosephK
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Homework Statement


1. Find the general solution to the differential equation:
y''-5y'+6y = 0


Homework Equations





The Attempt at a Solution


m^2 - 5m + 6 = 0
(m-1)(m-5) = 0
y' = Ae^x+Be^5x
 
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JosephK said:

Homework Statement


1. Find the general solution to the differential equation:
y''-5y'+6y = 0


Homework Equations





The Attempt at a Solution


m^2 - 5m + 6 = 0
(m-1)(m-5) = 0
Your factorization is incorrect. (m - 1)(m - 5) = m2 - 6m + 5, not m2 - 5m + 6.
JosephK said:
y' = Ae^x+Be^5x
 
This cannot be factored.
 
JosephK said:
This cannot be factored.
(m - 3)(m - 2) ?
 
So the answer to this differential equation is

y = c1e^3x+c2e^2x?
 
Yes, and you can check for yourself that your solution satisfies the differential equation. It's always a good idea to check.
 

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