Intro to Differential Equations Problem #1

JosephK
Messages
38
Reaction score
2

Homework Statement


1. Find the general solution to the differential equation:
y''-5y'+6y = 0


Homework Equations





The Attempt at a Solution


m^2 - 5m + 6 = 0
(m-1)(m-5) = 0
y' = Ae^x+Be^5x
 
Physics news on Phys.org
JosephK said:

Homework Statement


1. Find the general solution to the differential equation:
y''-5y'+6y = 0


Homework Equations





The Attempt at a Solution


m^2 - 5m + 6 = 0
(m-1)(m-5) = 0
Your factorization is incorrect. (m - 1)(m - 5) = m2 - 6m + 5, not m2 - 5m + 6.
JosephK said:
y' = Ae^x+Be^5x
 
This cannot be factored.
 
JosephK said:
This cannot be factored.
(m - 3)(m - 2) ?
 
So the answer to this differential equation is

y = c1e^3x+c2e^2x?
 
Yes, and you can check for yourself that your solution satisfies the differential equation. It's always a good idea to check.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top