Inverse Fourier, can't factor denominator, can't use partial frac.

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SUMMARY

The discussion centers on finding the Inverse Fourier Transform of the function [ jω+2 ] / [ (jω)² + 5jω + 9 ]. The main challenge is the inability to factor the denominator, which is a quadratic expression. Users suggest that the denominator can indeed be factored by identifying its roots, despite initial concerns about it leading to a complex solution. The conversation emphasizes the importance of manipulating the expression correctly to utilize Fourier Transform tables effectively.

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fishingspree2
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Homework Statement



Inverse Fourier of:
[ jω+2 ] / [ (jω)2 +5jω+9 ] where j = sqrt(-1)

I tried using partial fractions but the denominator can't be factored...I tried completing the square on the denominator but I get a sum of squares.

What can I try? I am sure I don't have to use the formal definition using the integral, there has to be a way of manipulating it to be able to use the table.

thank you!
 
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fishingspree2 said:

Homework Statement



Inverse Fourier of:
[ jω+2 ] / [ (jω)2 +5jω+9 ] where j = sqrt(-1)

I tried using partial fractions but the denominator can't be factored...I tried completing the square on the denominator but I get a sum of squares.

What can I try? I am sure I don't have to use the formal definition using the integral, there has to be a way of manipulating it to be able to use the table.

thank you!

Why would you say the denominator can't be factored? It is just a quadratic in ω, so certainly has two roots.

RGV
 
Alright, I will try to see if it leads me somewhere, do you think I'll be able to solve it this way? it seems like it will get messy
 

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