Inverse Function Theorem proof in Rudin

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transphenomen
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I am reading the proof of the Inverse Function Theorem in baby Rudin and I have a question about it. How does associating a function phi(x) (equation 48) with each point y tell us anything about if f(x) is one-to-one? I'll show the proof below. Also, if f'(a) = A, and f(x)=x2, what would A-1 be?
 
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  • Page from a textbook showing the Inverse Function Theorem: statement 9.24 with parts (a) and (b), a component-form interpretation, and the start of the proof with equation (46), 2λ||A^-1|| = 1.
    Inverse 1.jpg
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  • Scanned page of a mathematical proof, the Inverse Function Theorem from Rudin, with numbered equations (47) to (51) including phi(x) = x + A^{-1}(y - f(x)) and estimates on norms.
    Inverse 2.jpg
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  • Page of a mathematical proof showing equations (51) and (52) with inequality and the derivative of g expressed as the inverse of f' evaluated at g(y), followed by a remark citing Nijenhuis.
    Inverse 3.jpg
    59.3 KB · Views: 606
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The exact same equation had me freaking out for a while.

You can think of φ(x) = x + A⁻¹(y - f(x)) as coming from f(x) = f(x₀) + f'(x)(x - x₀),
& it's a way of introducing the concept of a fixed point so we can use the contraction
principle. You basically want to show that |φ'(x)| < ½ & then use theorem 9.19
|φ(b) - φ(a)| ≤ M(b - a) & with M = ½ you have a contraction mapping, thus by the
contraction principle you have that for every y it's associated function φ must be 1-1.