MHB Inverse Integral: $\int \frac{x^2\cos^{-1}\left(x\sqrt{x}\right)}{(1-x^3)^2}dx$

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$\displaystyle \int \frac{x^2\cos^{-1}\left(x\sqrt{x}\right)}{(1-x^3)^2}dx$
 
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integrate by parts dv = \frac{x^2}{(1-x^3)^2} and u = \cos ^{-1} (x \sqrt{x} )
 
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