1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Inverse Laplace Transform with e^{a s}

  1. Apr 8, 2015 #1
    1. The problem statement, all variables and given/known data
    How can I take the Inverse Laplace Transform of $F(s) = \frac{d}{ds}\left(\frac{1-e^{5s}}{s}\right)$?
    I have tried going with inverse of the derivative and convolution (even tried evaluating the derivative and go from there) but although I can get to some results none of them seems to make sense to me, as for example $f(t) = t(H_{-5} - 1)$, though I don't think this is even correct. Any help is greatly appreciated.

    2. Relevant equations
    $L{f} = F(s)$
    $L{f*g} = F(s)G(s)
     
  2. jcsd
  3. Apr 8, 2015 #2
    Should that be
    $$F(s) = \frac{d}{ds}\left(\frac{1-e^{-5s}}{s}\right)$$
    ?
    In that case ##t(H(t-5) - 1) ## should be correct (for t>0). As written above (without the minus in the exponent) the inverse expression does not converge. What is causing you uncertainty?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Inverse Laplace Transform with e^{a s}
Loading...