- #1
OjBinge
- 1
- 0
Does anyone know the inverse laplace transformation of the following:
(se^-s)/(s^(2)+1)
(se^-s)/(s^(2)+1)
Inverse Laplace Transformation Problem
- Thread starter OjBinge
- Start date
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- Inverse Laplace Transformation
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The discussion focuses on finding the inverse Laplace transformation of the function (se^-s)/(s^2+1). The solution involves using Maple 9 to simplify the expression by factoring out e^-s. It is suggested to convert e^-s into a unit step function U(t-a), allowing for the application of the inverse transformation. The final result combines the unit step function with F(s) to yield the complete solution. This approach provides a structured method for solving inverse Laplace transformations involving exponential terms.
- #2
- #3
faust9
- 690
- 2
pull out the e^{-s} leaving:
L^{-1}{ \{ \frac{s}{s^2+1} \}=f(t-a)
Now, the e can be converted to a unit step function U(t-a), and f(s-a) should be apparent.
Combine the unit step function with F(s) to get an end result.
L^{-1}{ \{ \frac{s}{s^2+1} \}=f(t-a)
Now, the e can be converted to a unit step function U(t-a), and f(s-a) should be apparent.
Combine the unit step function with F(s) to get an end result.
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