Inverse Laplace Transformations

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SUMMARY

The discussion focuses on finding the inverse Laplace transforms of two functions: \( \frac{2}{s^2+3s-4} \) and \( \frac{2s+1}{s^2-2s+2} \). The first function can be solved using partial fraction decomposition, yielding the result \( \frac{2}{5}e^t - \frac{2}{5}e^{-4} \). The second function requires completing the square and also results in a combination of exponential and trigonometric functions, specifically \( 2e^{t}\cos(t) + 3e^{t}\sin(t) \). The participants emphasize the importance of using a clear inverse Laplace transform table for reference.

PREREQUISITES
  • Understanding of inverse Laplace transforms
  • Familiarity with partial fraction decomposition
  • Knowledge of completing the square in algebra
  • Ability to interpret Laplace transform tables
NEXT STEPS
  • Study the method of partial fraction decomposition in detail
  • Learn how to complete the square for quadratic expressions
  • Explore various inverse Laplace transform tables for clarity
  • Practice solving inverse Laplace transforms with different functions
USEFUL FOR

Students and educators in engineering and mathematics, particularly those focusing on differential equations and control systems, will benefit from this discussion.

jimmypoopins
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Homework Statement


Find the inverse Laplace transform of the given functions:
3. [tex]\frac{2}{s^2+3s-4}[/tex]

7. [tex]\frac{2s+1}{s^2-2s+2}[/tex]

Homework Equations


Inverse Laplace Transform Table

The Attempt at a Solution


on 3. i made the denominator look like [tex](s+4)(s-1)[/tex] but i got lost from there. i couldn't find anything on the table resembling the equation.

on 7. i completed the square and got [tex]\frac{2s+1}{(s-1)^2+1}[/tex], which resembles [tex]\frac{s-a}{(s-a)^2+b^2}[/tex] on the table, yet i can't seem to make the numerator look like [tex](s-a)[/tex].

if it helps anyone, the answers are 3. [tex]\frac{2}{5}e^t-\frac{2}{5}e^{-4}[/tex] and 7. [tex]2e^{t}cos(t)+3e^{t}sin(t)[/tex].

thanks in advance.edit: p.s. if anyone has a better table of inverse laplace transformations, the one i posted is really hard to read. I'm using the one in my book but it might be useful, if you need to refer to one in a table when trying to help, to refer to a table you're more comfortable reading.
 
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For the first one, use partial fractions to write the problem as A/(s-1)+B/(s+4) (find the constants A and B). Break up the second fraction as well. Write it as 2(s-1)/((s-1)^2+1) +C/((s-1)^2+1) (find the constant C). Use the linearity of the laplace transform.
 
Last edited:
Dick said:
For the first one, use partial fractions to write the problem as A/(s-1)+B/(s+4) (find the constants A and B). Break up the second fraction as well. Write it as 2(s-1)/((s-1)^2+1) +C/((s-1)^2+1) (find the constant C). Use the linearity of the laplace transform.

thank you very much. I'm really bad with partial fractions, so i guess my brain sort of tried to not think of that method. i guess i'll touch up on them because this chapter is filled with inverse laplace transformations.
 

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