- #1

- 299

- 0

## Homework Statement

Define [tex]T:P_1 \rightarrow P_1[/tex] by T(a+bx)=(a-b)+ax. Check as to whether T has an inverse or not and if it has, find [tex]T^{-1}[/tex]

## Homework Equations

[tex]T^{-1}(T(v))=v[/tex]

## The Attempt at a Solution

The range of T is P1, so T is one-to-one. The inverse of T is therefore

[tex]T^{-1}((a-b)+ax)=(a+bx)[/tex]

Is my reasoning sound?

Thanks for the help!

phyz

Last edited: