Inverse Trig Equation Comparison: Arcsec vs Arctan

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SUMMARY

The discussion centers on the equivalence of the inverse trigonometric functions arcsec and arctan in the context of the equation arcsec(3x/4) versus arctan(4/sqrt(9x^2 - 16)). The user initially believes these functions are not equivalent but later suggests that arccsc(3x/4) may equal arctan(4/sqrt(9x^2 - 16)). The conclusion drawn is that while arcsec and arctan are distinct functions, the transformation involving arccsc indicates a deeper relationship between these inverse functions under specific conditions.

PREREQUISITES
  • Understanding of inverse trigonometric functions, specifically arcsec and arctan.
  • Familiarity with algebraic manipulation involving square roots and rational expressions.
  • Knowledge of trigonometric identities and their applications in solving equations.
  • Basic calculus concepts to analyze function behavior and equivalence.
NEXT STEPS
  • Study the properties and graphs of inverse trigonometric functions, focusing on arcsec and arctan.
  • Explore the relationship between arcsec and arccsc through trigonometric identities.
  • Learn how to manipulate and simplify expressions involving square roots in trigonometric equations.
  • Investigate the conditions under which different inverse trigonometric functions can be equivalent.
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Students studying trigonometry, mathematics educators, and anyone looking to deepen their understanding of inverse trigonometric functions and their applications in solving equations.

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Homework Statement



I have knocked a problem down to:

[tex]-arcsec \frac{3x}{4}[/tex]

but my textbook gives the answer as:

[tex]arctan \frac{4}{\sqrt{9x^2 - 16}}[/tex]

Are these somehow equivalent?

Thanks

Homework Equations





The Attempt at a Solution

 
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I don't think so. However, I get arccsc (3x/4) being equal to arctan(4/sqrt(9x^2 - 16))
 

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