Inverse Trig function derivative

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SUMMARY

The discussion focuses on finding the derivative of the function y = arctan(√(3x² - 1)). The derivative of arctan(x) is established as 1/(1 + x²), but the challenge arises when substituting a more complex expression like √(3x² - 1). The correct approach involves applying the chain rule to differentiate the function, leading to the derivative y' = (3x)/(1 + (3x² - 1)). This method is confirmed through a similar example where y = arctan(x²) is differentiated successfully.

PREREQUISITES
  • Understanding of derivatives and differentiation rules
  • Familiarity with the chain rule in calculus
  • Knowledge of inverse trigonometric functions
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Study the chain rule in depth for complex functions
  • Learn about the derivatives of inverse trigonometric functions
  • Practice differentiating composite functions
  • Explore applications of derivatives in real-world scenarios
USEFUL FOR

Students studying calculus, particularly those focusing on derivatives of inverse functions, and educators seeking to clarify concepts related to differentiation.

EvilBunny
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Homework Statement



Let

arctan ([tex]\sqrt{3x^2 -1}[/tex])


then dy/dx


Well I know that the derivative of arctanx is

1/ 1 + x ² but when I got something other then simply x I don't know how to proceed
 
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x=the radical

example

[tex]y=\arctan{(x^2)}[/tex]

[tex]y'=\frac{2x}{1+(x^2)^2}[/tex]
 
Neat I get it, thanks.
 

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