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Inverse Trig function derivative

  1. Nov 22, 2007 #1
    1. The problem statement, all variables and given/known data

    Let

    arctan ([tex]\sqrt{3x^2 -1}[/tex])


    then dy/dx


    Well I know that the derivative of arctanx is

    1/ 1 + x ² but when I got something other then simply x I don't know how to proceed
     
  2. jcsd
  3. Nov 22, 2007 #2
    x=the radical

    example

    [tex]y=\arctan{(x^2)}[/tex]

    [tex]y'=\frac{2x}{1+(x^2)^2}[/tex]
     
  4. Nov 22, 2007 #3
    Neat I get it, thanks.
     
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