# Inverse Trig function derivative

## Homework Statement

Let

arctan ($$\sqrt{3x^2 -1}$$)

then dy/dx

Well I know that the derivative of arctanx is

1/ 1 + x ² but when I got something other then simply x I don't know how to proceed

## Answers and Replies

x=the radical

example

$$y=\arctan{(x^2)}$$

$$y'=\frac{2x}{1+(x^2)^2}$$

Neat I get it, thanks.