Inverting Series: Solving for z in Powers of x

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Discussion Overview

The discussion revolves around the concept of inverting a series, specifically how to solve for z in powers of x given a series representation. Participants explore the general idea behind inverting series functions and seek clarification on the terminology used in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant asks how to invert a series and expresses uncertainty about the correctness of their proposed solution for z in terms of x.
  • Another participant provides a link to a resource on series reversion, indicating that the topic is complex.
  • A third participant notes the potential confusion between "inversion" and "reversion," suggesting that terminology may affect understanding.
  • The initial poster acknowledges that their terminology may have limited the information they received.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the terminology or the methods for inverting series, and the discussion remains unresolved regarding the correctness and proof of the proposed approach.

Contextual Notes

There is a lack of clarity on the definitions and assumptions related to series inversion and reversion, which may affect the understanding of the topic.

qbslug
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How do you invert a series? Can't find any information on it.
I need to invert a function and solve for z in powers of x

[tex] x = \sum_{n=1}^\infty\\b_n z^n[/tex]

I'm guessing we can just say

[tex] z = \sum_{n=1}^\infty\\a_n x^n[/tex]

But if this is right I don't know why its right or if it can be proven.
I would like to know the general idea behind inverting series functions and why it works.
 
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Pretty darn complicated! Note that the term "reversion" is used since "inversion" could be confused with finding the reciprocal, 1/z.
 
Ok thanks I guess I wasn't getting much information about it because I was referring to it as "inversion"
 

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