Investigate Convergence of tanx Series: Find Common Ratio & Sum to Infinity

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SUMMARY

The discussion focuses on the convergence of the sequence defined by tanx, tan2x, tan3x, ..., tannx for x in the interval (-90, 90) degrees. The series can be expressed as a geometric series, specifically Σ(ξ^n) where ξ = tan(x), which converges when |ξ| < 1, leading to the conclusion that convergence occurs for -π/4 < x < π/4. The sum to infinity of the series is derived as 1 / (1 - tan(x)), confirming the application of the geometric series sum formula.

PREREQUISITES
  • Understanding of geometric series and their convergence criteria.
  • Knowledge of trigonometric functions, specifically the tangent function.
  • Familiarity with the concept of limits and intervals in calculus.
  • Ability to manipulate algebraic expressions involving trigonometric functions.
NEXT STEPS
  • Study the properties of geometric series and their convergence conditions.
  • Explore the behavior of the tangent function within the specified interval.
  • Learn about the derivation of the sum to infinity for geometric series.
  • Investigate the implications of undefined values in trigonometric functions, such as tan(45).
USEFUL FOR

Mathematicians, students studying calculus, and anyone interested in the convergence of trigonometric series and their applications in mathematical analysis.

Alexeia
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Hi,

Please help me with this question: Investigate the convergence of the sequence tanx;tan2x;tan3x;...;tannx for xE(-90;90 degrees). Steps to follow: Find common ratio. Draw the graph. For which values will x converge. Determine sum to infinity.

I did try to solve, but file type too big to upload my answers.

Please help..

Thanks
 
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Alexeia said:
Hi,

Please help me with this question: Investigate the convergence of the sequence tanx;tan2x;tan3x;...;tannx for xE(-90;90 degrees). Steps to follow: Find common ratio. Draw the graph. For which values will x converge. Determine sum to infinity.

I did try to solve, but file type too big to upload my answers.

Please help..

Thanks

Setting $\tan x = \xi$ the series to be analized is $\displaystyle \sum_{n = 0}^{\infty} \xi^{n}$, which is 'geometrical' and converges for $|\xi|< 1 \implies -\frac{\pi}{4} < x < \frac{\pi}{4}$... in case of convergence is $\displaystyle \sum_{n=0}^{\infty} \tan^{n} x = \frac{1}{1 - \tan x}$...

Kind regards

$\chi$ $\sigma$

P.S. The formula for geometric sums is in...

Geometric Series -- from Wolfram MathWorld
 
Last edited:
Thank you,

The last part, how do you derive that the sum to infinity is 1 \div(1 - tanx)? Is it according to the Sum to infinity formula? To find the answer do I use 1 \div(1 - tan(45))? 1\div1 - tan(45) , Cant divide by 0.. ? Or do I just leave it as 1\div(1 - tanx)
 

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