Ionization Energy (Quantum Mechanics)

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SUMMARY

The discussion centers on calculating the ionization energy of krypton using ultraviolet radiation of wavelength 58.4 nm. The participant attempted to apply the Lyman series and the ionization energy formula, Ionization energy = hcR/n², but encountered difficulties due to krypton's multi-electron structure. The expected ionization energy is 14 eV, but the calculations did not yield this result. The participant was advised to relate the problem to the photoelectric effect, emphasizing the importance of understanding the energy of incident photons versus emitted electrons.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Familiarity with the Lyman series and Rydberg constant
  • Knowledge of quantum mechanics principles
  • Basic proficiency in energy calculations using E=hv and E=0.5mv²
NEXT STEPS
  • Study the photoelectric effect and its implications for multi-electron atoms
  • Learn about the Rydberg formula and its application to different elements
  • Explore advanced quantum mechanics concepts related to electron configurations
  • Investigate the relationship between photon energy and electron emission in multi-electron systems
USEFUL FOR

Students and educators in quantum mechanics, physicists focusing on atomic structure, and anyone studying the ionization energies of noble gases like krypton.

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Homework Statement



When ultraviolet radiation of wavelength 58.4 nm from a helium lamp is directed on to a sample of krypton, electrons are ejected with a speed of 1.59 Mm/s. Calculate the ionization energy of Krypton.

Homework Equations



E=hv, \frac{1}{λ}=R(1- \frac{1}{n<sup>2</sup>} ) <- Lyman series
Ionization energy = \frac{hcR}{n<sup>2</sup>}

The Attempt at a Solution



I used the Lyman series to try and find the Rydberg constant for Krypton (with n=4), then substituted that value into the Ionization energy equation with n = 4 again. I'm given that the answer should be 14 eV, but I didn't get that result.

My confusion is how these equations relate to the ionization of krypton since the equations assume a single electron atom, which krypton is not. Furthermore, I can't find a use for the velocity (E= 0.5mv2 also doesn't give the correct answer).

Any help in figuring out how to approach this problem would be greatly appreciated.
 
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Why do you care about the structure of krypton's spectrum? You have the energy of incident photons, you have the energy of emitted electrons. Where is the difference at?
 
The Lyman type of series only applies to one-electron atoms or ions. Try relating this problem to the photoelectric effect.
 

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