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Is the explanation at the end of the video correct?
The discussion centers on the behavior of an infrared (IR) laser when directed at a radiometer vane, specifically addressing the phenomenon of the glowing spot produced on the metal surface. Participants analyze the thermal effects, questioning the roles of conduction, convection, and radiation in this process. Key points include the assertion that convection diminishes the effect in air, while the thinness of the vanes may limit conduction cooling. The Stefan-Boltzmann law is referenced to calculate the temperature based on the laser's output power and dot size, emphasizing the need to consider absorbed power rather than incident power.
PREREQUISITESPhysicists, engineers, and researchers interested in laser applications, thermal dynamics, and material science, particularly those studying the interactions between lasers and various materials.
Sorry, yes the question should have included more detail...Vanadium 50 said:@Swamp Thing , it's not like you are new here. "Here's a video, 'splain it to me" is a bad thread start. You've been here long enough to know what you get out of PF is proportional to what you put into PF.
He says the laser is heating the metal to incandescence. He also says that convection is the reason that it doesn't work in air.hmmm27 said:Conduction requires cross-section ; those vanes look pretty thin. I'm not sure why "radiation doesn't matter" : where does he think the glow is coming from ?
Unless you've perfect conduction, it's going to glow. Whether that glow extends far enough into the visible spectrum to see is another thing.Swamp Thing said:If radiation mattered, then it wouldn't have glowed even in vacuum.
I think P needs to be the power absorbed and so will be incident power minus reflected power.hmmm27 said:If we can ignore conduction and make enough other gross simplifications and assumptions to make a few eyes twitch here and there, we can stick the output power and dot size of the laser pretty much directly into the Stefan Boltzmann law to get the temperature.
Oh, definitely, but that would require knowing the composition of the leaf (which I imagine is carbon-deposited aluminum, but really have no clue).tech99 said:I think P needs to be the power absorbed and so will be incident power minus reflected power.