Iron ball hanging from a scale and suspended

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SUMMARY

The discussion centers on the physics of an iron ball suspended in a glass of water and its effects on scale readings. When the iron ball is submerged, the scale reading decreases due to the buoyant force acting on the ball, which counteracts its weight. The volume of water remains unchanged as the volume displaced by the ball equals its own volume. The weight of the glass of water is not affected by the ball's presence, as the total system weight remains constant.

PREREQUISITES
  • Understanding of Archimedes' Principle
  • Basic knowledge of buoyancy and forces
  • Familiarity with scale measurements
  • Concept of weight and volume displacement
NEXT STEPS
  • Study Archimedes' Principle in detail
  • Explore the concept of buoyant force and its calculations
  • Learn about scale calibration and measurement techniques
  • Investigate the relationship between weight, volume, and density
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Students of physics, educators teaching fluid mechanics, and anyone interested in understanding the principles of buoyancy and scale measurements.

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Iron ball hanging from a scale and suspended...

Iron ball hanging from a scale and suspended in a glass of water filled to the rim, what happens to the reading of the scale, volume of water, and weight of the glass of water?

The attempt at a solution: there's an FB that's equal to the weight of the water removed pushing on the ball upwards, then weight - FB is equal to the tension in the thread, which means weight is less, then reading is less, volume of water stays the same because the volume of the water removed is equal to the volume of the ball, weight of the glass is...i have no idea tbh!

please explain your answer! thanks :)
 
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