Irradiance at a point on a surface

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SUMMARY

The discussion clarifies that irradiance at a point on the outer sphere is indeed less than that on the inner sphere, as stated in the referenced book. The formula for irradiance is defined as flux divided by area, specifically flux/4π*r² for a sphere. This formula quantifies the total energy per unit time that passes through a specific area, emphasizing that the concept of a "point" is abstract and relates to an infinitesimal surface surrounding that point to determine its irradiance value.

PREREQUISITES
  • Understanding of basic physics concepts such as flux and irradiance.
  • Familiarity with spherical geometry and surface area calculations.
  • Knowledge of energy transfer principles in physics.
  • Basic mathematical skills for manipulating formulas.
NEXT STEPS
  • Research the concept of flux in electromagnetic theory.
  • Study the derivation and applications of the irradiance formula in different contexts.
  • Explore the relationship between irradiance and energy transfer in various materials.
  • Learn about the implications of irradiance in solar energy applications.
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Students of physics, educators explaining energy transfer concepts, and professionals in fields related to optics and solar energy systems.

Pilpellon
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My book states that "irradiance at a point on the outer sphere is less than irradiance at a point on the inner sphere."

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The formula is simple, it's flux/area. So in case of a sphere its flux/4π*r^2.
But my question is what exactly does this formula give? does it give the total flux that arrives on a point on the sphere? If so, what are the dimensions of that point? The book totally confused me on that part.
 
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power or flux (energy/time) per area = irradiance
It gives you how much energy per unit of time passes through some area.
No point is concerned, except for if around that point you draw an infinitesimal surface. So you can determine its value at those points.
 

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