Is 1 Mole of BaSO4 Equal to 1 Gram?

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Discussion Overview

The discussion revolves around the stoichiometry of the reaction between barium ions and sulfate ions to form barium sulfate. Participants are clarifying the relationship between moles and mass in the context of this reaction, specifically addressing whether one mole of barium sulfate corresponds to one gram.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant states that the mole ratio of barium ions to sulfate ions is 1:1, suggesting that one mole of each reactant would yield one mole of barium sulfate.
  • Another participant clarifies that while one mole of barium sulfate can be produced, it does not equate to one gram, emphasizing the distinction between moles and mass.
  • Further discussion highlights that the molar mass of barium sulfate is approximately 233 grams, indicating that one mole of it would weigh significantly more than one gram.

Areas of Agreement / Disagreement

Participants generally agree on the mole ratio and the production of one mole of barium sulfate, but there is disagreement regarding the mass, with some asserting that it cannot be one gram.

Contextual Notes

The discussion involves assumptions about reaction efficiency and the definitions of moles and mass, which are not fully explored or resolved.

kara
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I obtained a net ionic equn' as follows

Ba +2 (aq) + SO4 2- (aq) ----> BaSO4 (s)

Now I need clarification for the following question and my answer to it.

What is the max amount of solid product that could be obtained by reacting one mole of each reactant?

I believe that b/c of the mole ratio being 1:1 between both reactants and the product, so the max amount of solid product would be 1 mol, or 1 g.

Is this reasonable to state?
 
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kara said:
I obtained a net ionic equn' as follows

Ba +2 (aq) + SO4 2- (aq) ----> BaSO4 (s)

Now I need clarification for the following question and my answer to it.

What is the max amount of solid product that could be obtained by reacting one mole of each reactant?

I believe that b/c of the mole ratio being 1:1 between both reactants and the product, so the max amount of solid product would be 1 mol, or 1 g.

Is this reasonable to state?
Ba2+(aq) + SO42-(aq) ----> BaSO4 (s) is a one to one ratio (i.e. 1:1). So one mole of each reactant will produce one mole of the solid, if the reaction is 100% efficient. However, it will not produce one gram of the solid. Remember, the mole is not the same as mass. One mole of a substance contains 6.23 x 1023 molecules of the substance but one gram of a substance can contain different numbers of moles.

Remember that: Molar Mass / Mr (Units: g mol-1) = Mass / m (Units: g) / Moles / mol (Units mole)

So one mole of Carbon will have a mass of 12 grams but one mole of Hydrogen gas will have a mass of 2g.

So on the whole, what you were saying was true. :biggrin:

The Bob (2004 ©)
 
The Bob said:
However, it will not produce one gram of the solid.

(...)

So on the whole, what you were saying was true. :biggrin:

So was it true, or not ;)

kara: 1 mole, but not 1 gram.
 
Borek said:
So was it true, or not ;)

kara: 1 mole, but not 1 gram.

Borek
--
General Chemistry Software
www.pH-meter.info
Yer, yer... very funny... :biggrin: It was almost all true. It was just the little
, or 1g
that was not. So...

1 mole of BaSO4 is approx. 233 grams. Happy? :-p

The Bob (2004 ©)
 

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