Is 1-(sin^6x+cos^6x)=(3sin^2x)(cos^2x) a Valid Trigonometric Identity?

[larymac47]

1-(sin^6x+cos^6x)=(3sin^2x)(cos^2x)

I got this far:

1-(sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x)=(3sin^2x)(cos^2x)
1-(sin^4x-sin^2xcos^2x+cos^4x)=(3sin^2x)(cos^2x)

 

[jhae2.718]

I'd start by manipulating one of the sides.