- #1
Is ">=1" Valid for a Circle Equation?
- Thread starter DrMath
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Homework Help Overview
The discussion revolves around the validity of using the inequality ">= 1" in the context of a circle equation, specifically referencing the expression x² + y² ≥ 1 and its implications for the points that satisfy this condition.
Discussion Character
- Conceptual clarification, Assumption checking
Approaches and Questions Raised
- Some participants explore the meaning of the inequality in relation to circle equations, questioning how it differs from the equality case. Others discuss the geometric interpretation of the inequality in terms of points lying inside or outside the circle.
Discussion Status
The conversation includes various interpretations of the inequality and its geometric implications. Some participants provide insights into the nature of the points satisfying the inequality, while others engage in clarifying the mathematical expressions involved.
Contextual Notes
There are references to attached images or equations that are not visible in the thread, which may contain additional context or information relevant to the discussion. Participants also mention the use of vectors in relation to the problem, suggesting a potential shift in perspective.
- #2
rock.freak667
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if you mean x2+y2≥1 , then yes it is a 'circle' in essence but the points (x,y) that satisfy the inequality do not lie on the circle itself like if if it was x2+y2=1
- #3
tiny-tim
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Hi DrMath! 
(have a ≥ and try using the X2 and X2 tags just above the Reply box
)
Your picture says |z - 2j| ≥ 1 …
in other words, the magnitude of the "vector" from 2j to z has length ≥ 1 …
so z is the exterior (and boundary) of the circle of length 1 and centre at 2j
(btw, it's easier to use "vectors" rather than coordinates for as problem like this)
(have a ≥ and try using the X2 and X2 tags just above the Reply box
)Your picture says |z - 2j| ≥ 1 …
in other words, the magnitude of the "vector" from 2j to z has length ≥ 1 …
so z is the exterior (and boundary) of the circle of length 1 and centre at 2j
(btw, it's easier to use "vectors" rather than coordinates for as problem like this
)- #4
DrMath
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Thanks tiny-tim
oh.. how to become a Homework Helper here?
oh.. how to become a Homework Helper here?
- #5
tiny-tim
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just help people with their homework! Similar threads
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