DrMath
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Is ">=1" Valid for a Circle Equation?
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if you mean x2+y2≥1 , then yes it is a 'circle' in essence but the points (x,y) that satisfy the inequality do not lie on the circle itself like if if it was x2+y2=1
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Hi DrMath! 
(have a ≥ and try using the X2 and X2 tags just above the Reply box
)
Your picture says |z - 2j| ≥ 1 …
in other words, the magnitude of the "vector" from 2j to z has length ≥ 1 …
so z is the exterior (and boundary) of the circle of length 1 and centre at 2j
(btw, it's easier to use "vectors" rather than coordinates for as problem like this)
(have a ≥ and try using the X2 and X2 tags just above the Reply box
)Your picture says |z - 2j| ≥ 1 …
in other words, the magnitude of the "vector" from 2j to z has length ≥ 1 …
so z is the exterior (and boundary) of the circle of length 1 and centre at 2j
(btw, it's easier to use "vectors" rather than coordinates for as problem like this
)
DrMath
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Thanks tiny-tim
oh.. how to become a Homework Helper here?
oh.. how to become a Homework Helper here?
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just help people with their homework!