Is (5*Pi)/6 the Correct Volume for the Intersection of a Paraboloid and Cone?

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SUMMARY

The volume of the intersection of the paraboloid defined by the equation z=2-x^2-y^2 and the cone described by z^2=x^2+y^2 is accurately calculated as (5*Pi)/6. This conclusion is reached by employing cylindrical coordinates to evaluate the bounded domain D, which is defined by the inequalities x^2+y^2 ≤ 1 and sqrt(x^2+y^2) ≤ z ≤ 2-x^2-y^2. The calculation has been confirmed as correct by multiple contributors in the discussion.

PREREQUISITES
  • Cylindrical coordinates
  • Understanding of volume integration
  • Knowledge of paraboloids and cones in three-dimensional space
  • Familiarity with the equations z=2-x^2-y^2 and z^2=x^2+y^2
NEXT STEPS
  • Study the application of triple integrals in cylindrical coordinates
  • Explore the derivation of volume for various solid shapes
  • Learn about the geometric interpretation of paraboloids and cones
  • Investigate other coordinate systems for volume calculations, such as spherical coordinates
USEFUL FOR

Mathematicians, physics students, and anyone involved in calculus or geometric analysis will benefit from this discussion, particularly those focused on volume calculations of three-dimensional shapes.

Juggler123
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Just needing to check an answer really. The question is as follows;

The domain bounded by the surface of a paraboloid z=2-x^2-y^2 and that of a cone z^2=x^2+y^2 is given by D = ( x,y,z : x^2+y^2 [tex]\leq[/tex] 1, sqrt(x^2+y^2) [tex]\leq[/tex] z [tex]\leq[/tex] 2-x^2-y^2 ). Find its volume using the appropriate coordinate system.

I've used cylindrical coordinates for this problem and found the answer to be (5*Pi)/6. Can anyone tell me if this is actually correct or have a made a mistake somewhere along the way?

Thanks!
 
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Juggler123 said:
Just needing to check an answer really. The question is as follows;

The domain bounded by the surface of a paraboloid z=2-x^2-y^2 and that of a cone z^2=x^2+y^2 is given by D = ( x,y,z : x^2+y^2 [tex]\leq[/tex] 1, sqrt(x^2+y^2) [tex]\leq[/tex] z [tex]\leq[/tex] 2-x^2-y^2 ). Find its volume using the appropriate coordinate system.

I've used cylindrical coordinates for this problem and found the answer to be (5*Pi)/6. Can anyone tell me if this is actually correct or have a made a mistake somewhere along the way?

Thanks!

That's exactly correct.
 

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