Is (a,b,c) where b=a+c a Subspace of r^3?

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SUMMARY

The set of all vectors of the form (a, b, c) where b = a + c is indeed a subspace of R³. This conclusion is supported by the closure properties under addition and scalar multiplication. Specifically, the vectors can be expressed as linear combinations of the basis vectors (1, 1, 0) and (0, 1, 1), confirming that it forms a two-dimensional subspace. The textbook's assertion that it is not a subspace is incorrect.

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Homework Statement



Determine whether the following is a Subspace of r^3:

All vectors of the form (a,b,c), where b=a+c

The Attempt at a Solution



The answer in the book says it is not a subspace but I can only find examples that show it is a Subspace I.e.

Let u=(a,a+c,c)=(1,2,1), v=(a,a+c,c)=(2,4,2) and k=2 then

U+v=(3,6,3)=(a,a+c,c) so it's closed under addition

Ku=2(a,a+c,c)=2(1,2,1)=(2,4,2)=(a,a+c,c) so it is closed under scalar multiplication

Maybe I don't understand the concept correctly am I doing something wrong?
 
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If your textbook says this is not a subspace, it is wrong. It is, exactly as you say, the subspace of R3 of all vectors of the form (a, b, c)= (a, a+ c, c)= (a, a, 0)+ (0, c, c)= a(1, 1, 0)+ c(0, 1, 1). In other words, it is the two dimensional subspace with (1, 1, 0) and (0, 1, 1) as basis.
 

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