Is a Discrete Group of Rotations Cyclic?

  • Thread starter Thread starter SNOOTCHIEBOOCHEE
  • Start date Start date
  • Tags Tags
    Discrete Groups
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
3 replies · 2K views
SNOOTCHIEBOOCHEE
Messages
141
Reaction score
0

Homework Statement



Prove that a discrete group G cosisting of rotations about the origin is cyclic and is generated by [tex]\rho_{\theta}[/tex] where [tex]\theta[/tex] is the smallest angle of rotation in G

The Attempt at a Solution



since G is by definition a discrete group we know that if [tex]\rho[/tex] is a rotation in G about some point through a non zero angle [tex]\theta[/tex] the the angle [tex]\theta[/tex] is at least [tex]\epsilon[/tex]:|[tex]\theta[/tex]|[tex]\geq\epsilon[/tex]

But i don't know how to apply this definition to show that G is cyclic. Is this definition even useful?
 
Physics news on Phys.org
Ok, if you pick theta to be the smallest angle (which you can do since the rotations are discrete), then all of the rotations n*theta for n an integer are in the group. If that's the whole group, then you are done since it's cyclic. If not there a rotation phi in the group that isn't equal to n*theta for any n. Can you take the next step?
 
with that i can show that there is a non zero positive rotation less than theta, a contradiction. Is that it?
 
SNOOTCHIEBOOCHEE said:
with that i can show that there is a non zero positive rotation less than theta, a contradiction. Is that it?

It sure is.