Is a nth order ODE considered linear if n=2?

  • Thread starter Thread starter Saladsamurai
  • Start date Start date
  • Tags Tags
    Linearity
Click For Summary
An nth order ordinary differential equation (ODE) is considered linear if it is linear in the dependent variable y and its derivatives, regardless of the order n. For example, the equation y'' + y = 0 is second-order and linear because it involves the second derivative y'' and the first degree of y. In contrast, equations like (y'')^2 + ay^3 = 0 are second-order but non-linear due to the powers of the derivatives and the dependent variable. The right-hand side of a linear ODE can be zero or a function of the independent variable, including constants. Understanding the distinction between the order of derivatives and their degree is crucial for identifying the linearity of ODEs.
Saladsamurai
Messages
3,009
Reaction score
7
I am reading through my Diff Eqs Text and I follow most of the lingo. However I am just a tad confused by the statement:

An nth order ODE is said to be linear if F is linear in y,y',...y^(n)

Then it gives the example:

a_n(x)\frac{d^ny}{dx^n}+a_{n-1}(x)..+a_0(x)y=g(x)

It then says: 'On the left-hand side of the above equation the dependent variable y and all of its derivatives, y,y',y'',...y^n are of the first degree.

Clearly I missed something in Calc. If n=2, I have: \frac{d^2y}{dx^2}

Why is this linear if n=2?

Thanks,
Casey
 
Physics news on Phys.org
You're confusing the *order* of the derivative with its *degree* in the equation.

y'' + y = 0

is a second-order linear equation. Second-order because the highest order derivative in the equation is a second dervative. Linear because the equation itself is linear in both y'' and y.

In contrast:

(y'')^2 + ay^3 = 0

is a second-order NON-linear D.E. Second-order for the same reason. NON-linear because it is QUADRATIC in y'' and CUBIC in y. I hope this clears things up.
 
Last edited:
cepheid said:
You're confusing the *order* of the derivative with its *degree* in the equation.

y'' + y = 0

is a second-order linear equation. Second-order because the highest order derivative in the equation is a second dervative. Linear because the equation itself is linear in both y'' and y.

In contrast:

(y'')^2 + ay^3 = 0

is a second-order NON-linear D.E. Second-order for the same reason. NON-linear because it is QUADRATIC in y'' and CUBIC in y. I hope this clears things up.

I think it does. y' just means "the 1st derivative" and similarly for y" however if either one y' or y" or y for that matter were raised to any power above 1, the DE would no longer be linear.

Thanks!
 
Yes, that is correct. Also note that other "non-linear" functions of the dependent variable, y or its derivatives, such as sin(y) or exp(y"), would make the equation non-linear.
 
HallsofIvy said:
Yes, that is correct. Also note that other "non-linear" functions of the dependent variable, y or its derivatives, such as sin(y) or exp(y"), would make the equation non-linear.

Great, thanks Halls and cepheid. Hey also, I know that the right-hand side can be equal to 0 or a function of the independent variable; what about a constant?

Like \frac{d^2y}{dx^2}-\frac{dy}{dx}+6y=7 ?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
6
Views
2K
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
3
Views
2K
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K