Is A subset of B in this proof involving sets and integers?

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SUMMARY

The discussion centers on proving that set A, defined as A = { pi + 2k pi | k ∈ Z }, is a subset of set B, defined as B = {(- pi / 3) + (2k pi / 3) | k ∈ A }. The proof involves substituting elements from set A into the expression for set B. The solution was achieved by replacing pi with -pi/3 + 4pi/3, confirming that every element of A can be expressed in terms of elements in B.

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  • Familiarity with integer sets and the notation k ∈ Z
  • Knowledge of mathematical proofs and substitutions
  • Basic trigonometric identities involving pi
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Andrax
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Homework Statement



A = { pi + 2k pi / k \in Z }
B = {(- pi / 3) + (2k pi / 3 ) / k \in A }
Prove that A C B

Homework Equations


A C B = \forallXE E : x \ni A \Rightarrow X \ni B

The Attempt at a Solution


\ni[k E Z ]: x = pi + 2k pi
\ni[k E Z ]: x = pi ( 1 + 2k)
I'm sure i need to get a k and replace it with k' to prove that it belongs to B
 
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Edit : solved it by replacing pi by -pi/3+4pi/3 which led to the correct answer
 

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