Prove A C B for Set Theory: Help with Pi and Integers

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SUMMARY

The discussion focuses on proving the set inclusion A ⊆ B for the sets defined as A = { π + 2kπ | k ∈ Z } and B = { (-π/3) + (2kπ/3) | k ∈ A }. The user successfully demonstrated the inclusion by substituting π with the expression -π/3 + 4π/3, confirming that elements of A can be expressed in terms of elements of B. This proof utilizes the properties of integer multiples and transformations within set theory.

PREREQUISITES
  • Understanding of set theory notation and concepts
  • Familiarity with integer sets (Z) and their properties
  • Knowledge of mathematical proofs and logical reasoning
  • Basic understanding of trigonometric constants, specifically π
NEXT STEPS
  • Study the properties of set inclusion and equivalence in set theory
  • Learn about transformations and substitutions in mathematical proofs
  • Explore integer multiples and their applications in set definitions
  • Investigate the implications of trigonometric identities in set theory
USEFUL FOR

Mathematics students, educators, and anyone interested in set theory and mathematical proofs, particularly those working with trigonometric functions and integer sets.

Andrax
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Homework Statement



A = { pi + 2k pi / k \in Z }
B = {(- pi / 3) + (2k pi / 3 ) / k \in A }
Prove that A C B

Homework Equations


A C B = \forallXE E : x \ni A \Rightarrow X \ni B

The Attempt at a Solution


\ni[k E Z ]: x = pi + 2k pi
\ni[k E Z ]: x = pi ( 1 + 2k)
I'm sure i need to get a k and replace it with k' to prove that it belongs to B
 
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Edit : solved it by replacing pi by -pi/3+4pi/3 which led to the correct answer.
 

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