Is an Eigenvector of A also an Eigenvector of A^2?

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Homework Help Overview

The discussion revolves around the properties of eigenvectors in relation to a matrix A and its square, A^2. Participants are exploring whether an eigenvector of A is also an eigenvector of A^2.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the eigenvector equation and the application of the matrix A multiple times. Some suggest simplifying the approach by applying the matrix directly to the eigenvector, while others propose using properties of matrices to manipulate the expressions involved.

Discussion Status

There is an ongoing exploration of different methods to demonstrate the relationship between the eigenvector of A and A^2. Some participants have provided alternative perspectives and suggestions for simplifying the reasoning, but no consensus has been reached on a definitive method.

Contextual Notes

Participants are working within the constraints of proving the relationship without providing a complete solution. The original poster's attempt includes specific notation and steps that may be subject to scrutiny.

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Homework Statement


Prove that if s is an eigenvector of matrix A, then it is also an eigenvector
of matrix A^2.

Homework Equations



As=Ics

The Attempt at a Solution


We know that As=Ics.
So AAs=AIcs
A(As)=A(Ics)
A(As)-A(Ics)=0
A(As-Ics)=0
Since As-Ics=0
A(As-Ics)=A(0)=0
 
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Looks about right, but perhaps a bit cumbersome. Just apply the matrix twice to the vector s. In your notation:
(AA)s = A(As) = A(Ics) = Ic(As) = (Ic)^2s
Which is all you need.
 
I think it is correct, although admittely I didn't check all of it.
There is an easier way.
From the "relevant equations", you see that you have to show that
A^2 s = I k s
for some number k.

If you start from
A^2 s = A I c s,
can you use two properties of matrices to get the A in front of the s and use A s = I c s again?

[edit]Actually xepma has already given you the complete answer :-p [/edit]
 
Thanks for the help!
 

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