Is Angular Acceleration Zero in Constant Rolling Motion?

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In constant rolling motion, the angular acceleration of a wheel is indeed zero, indicating that it is not speeding up or slowing down. The tangential velocity is uniform across all points on the rim, while the linear velocity at the rim is non-zero. The wheel rolls without slipping at the point of contact with the surface, which is crucial for maintaining constant motion. The discussion highlights that rolling motion can occur for various reasons, but the key point is that it does not necessarily imply acceleration. Understanding these principles is essential for solving related physics problems.
gcombina
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Homework Statement


Which statement concerning a wheel undergoing rolling motion is true?

(a) The angular acceleration of the wheel must be zero m/s2.

(b) The tangential velocity is the same for all points on the wheel.

(c) The linear velocity for all points on the rim of the wheel is non-zero.

(d) The tangential velocity is the same for all points on the rim of the wheel.

(e) There is no slipping at the point where the wheel touches the surface on which it is rolling

Homework Equations

The Attempt at a Solution



(a) Angular Acceleration

∝ = Δω/τ

I am confused on this first option, if the wheel is rolling, does it mean that there is a force pushing this wheel? (since there is friction), therefore IT IS accelerating.

Am I approaching this option correctly?
 
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gcombina said:
if the wheel is rolling, does it mean that there is a force pushing this wheel?
No.
 
so why is the wheel rolling? if there is air friction and the road friction?
 
gcombina said:
so why is the wheel rolling? if there is air friction and the road friction?
The short answer is, we don't know and we don't care why it is rolling. There are many possible reasons, and they don't all imply it's getting faster.
Which of the following would qualify as "a wheel undergoing rolling motion"?
  • a disc rolling freely down a ramp, accelerating
  • a disc which has rolled down a dip, but is now rolling freely up the other side
  • a car wheel, the car driving at constant speed
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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