Is Angular Momentum Conserved in Modified Newtonian Dynamics?

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SUMMARY

The discussion centers on the conservation of angular momentum within the framework of Modified Newtonian Dynamics (MOND), specifically under the condition where the force function is defined as F = m*f(a/a0)*a. For small accelerations, the function simplifies to f(a/a0) = a/a0, allowing for the analysis of motion in polar coordinates. The key conclusion is that angular momentum, defined as m*r(t) x v(t), remains conserved when examining the forces involved, particularly gravitational and centripetal forces.

PREREQUISITES
  • Understanding of Modified Newtonian Dynamics (MOND)
  • Familiarity with polar coordinates in physics
  • Knowledge of angular momentum and its mathematical representation
  • Basic principles of forces, including gravitational and centripetal forces
NEXT STEPS
  • Study the implications of Modified Newtonian Dynamics on celestial mechanics
  • Explore the mathematical derivation of angular momentum in polar coordinates
  • Investigate the relationship between gravitational and centripetal forces in orbital dynamics
  • Learn about the applications of conservation laws in non-classical mechanics
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Students and researchers in physics, particularly those focusing on dynamics, celestial mechanics, and the implications of Modified Newtonian Dynamics on angular momentum conservation.

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Homework Statement



For very low rates of acceleration, Newton's 2nd law has to be modified where F<vector>=m*f(a/a0)*a<vector>. For "small" values of a<vector>, f(a/a0) = a/a0.
Determine the component equations of motion for the case of f(a/a0) = a/a0 in polar coordinates (don't try to solve the radial equation!). Show that the angular momentum is conserved.

Homework Equations



F<vector> = m*f(a/a0)*r<double dot>

The Attempt at a Solution



Since we are dealing with orbits, I am assuming the the two forces are the gravitational and centripetal forces (or are they the same thing). I also can determine r<double dot> in polar coordinates.
 
Last edited:
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Angular momentum is m*r(t)xv(t). (x is cross product). What's the derivative of angular momentum? What properties of the force and the cross product can help you prove this derivative is zero?
 

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