Is Classical EM Field the Same as Photon Wave Function?

[Swamp Thing]

[QUOTE

They say it takes 9 minutes for the sunlight to travel to earth. You are saying it only looks like the field is propagating, but it isn't because the field is defined all over space.. so before the sunlight photons even reach the earth.. those same photon fields are already on earth?? and only the field is changing values making it looks like the sun light is travelling?

Although the field is defined all over space (time), no one says it can't have zero amplitude for a very large region. (Here the amplitude is the complex probability amplitude that you square to get detection probability).

So if we do an experiment in the lab that involves generating a field with exactly one photon at the event (Alice's Source Emits, t=0) then the field is defined accordingly. If the geometry is right, we can predict that this field will evolve over time and we end up with a high probability amplitude for the event (Bob's detector fires, $t=t_{propagation}$)

and only the field is changing values making it looks like the sun light is travelling?

In the sense described above, yes.

 

[Blue Scallop]

No there isn't. Classical EM field depends on only one position. However, it contains many photons so "Bohmization" requires a wave function that depends on many positions.

Haven't you seen Bill message in #56 (just before you posted). He said maybe. What is wrong with contents in the paper he gave:

http://cds.cern.ch/record/944002/files/0604169.pdf

 

[Demystifier]

Haven't you seen Bill message in #56 (just before you posted). He said maybe. What is wrong with contents in the paper he gave:

http://cds.cern.ch/record/944002/files/0604169.pdf

Nothing is wrong with that paper. But classical EM field is not the same thing as photon wave function, even if they satisfy the same Maxwell equations. For more details see
https://arxiv.org/abs/1205.1992 Sec. 8.3.3.5.