Is Cosh x > 1 True for All Values of x?

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Homework Help Overview

The discussion revolves around the mathematical statement regarding the hyperbolic cosine function, specifically whether cosh(x) is greater than 1 for all values of x. Participants are exploring the properties and definitions of the hyperbolic cosine function.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants express uncertainty about the truth of the statement, questioning the meaning of the question itself. Others attempt to clarify the definition of the hyperbolic cosine function and suggest using a Maclaurin series to analyze its behavior.

Discussion Status

The discussion is ongoing, with participants providing definitions and exploring the implications of the hyperbolic cosine function. There is a mix of interpretations and attempts to clarify the mathematical concepts involved.

Contextual Notes

Participants note potential confusion regarding the parameters and definitions involved in the problem, particularly around the use of coefficients and the notation of the hyperbolic cosine function.

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Homework Statement


True or false?

Cosh x > 1 for all x

The Attempt at a Solution



the answer is true, and I'm not sure why. if h is a coefficient, then I'm pretty sure I can think of some values of x and h that would be < 1.
For instance, if h=1 and x=\pi/3

What does the question even mean?
 
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Jules18 said:

Homework Statement


True or false?

Cosh x > 1 for all x

The Attempt at a Solution



the answer is true, and I'm not sure why. if h is a coefficient, then I'm pretty sure I can think of some values of x and h that would be < 1.
For instance, if h=1 and x=\pi/3

What does the question even mean?
cosh is short for hyperbolic cosine. h is not a parameter.

This function is defined as
cosh(x)~=~\frac{e^{x} + e^{-x}}{2}

Edit: no i in exponents

You might need to write the right side of the equation above as a Maclaurin series to show that cosh(x) >= 1 for all x.
 
Last edited:
cosh x = (Exp[x] + Exp[-x])/2
 
jakncoke, by Exp[x] do you mean ex where e is the constant that's approx. 2.718 ?
 
yes.
 

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