Is Cu(ClO4)2 Omitted in Net Ionic Equations?

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SUMMARY

Cu(ClO4)2 is indeed soluble and should not appear in the net ionic equation, which typically includes only the species that undergo a change. The discussion clarifies that while Cu(OH)2 is insoluble and must remain in the equation, soluble compounds like Cu(ClO4)2 are omitted. This distinction is crucial for accurately representing chemical reactions in net ionic form.

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ChrisEffinSmi
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I've been struggling with this for a while now. Cu(ClO4)2 is soluble so it should drop from both sides of the net ionic equation, right? Leaving only H20. Am I missing something?

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Cu(OH)2 is insoluble. There is a reason why it is marked with (s).

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methods
 
But if you have something solid like Cu(OH)2, you need to leave it in the equation, regardless of whether any of its ions (such as Cu2+) have separated on the other side of the equation.
 

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