Is Cu2+ Soluble with Cl-? Solubility Dependence on Charge and Size

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SUMMARY

The solubility of Cu2+ with Cl- is significantly different from that of Cu+. Cu2+ ions exhibit higher solubility due to their greater charge density and hydration energy compared to Cu+. The solubility product is inherently dependent on the solvent, typically assumed to be water unless specified otherwise. It is crucial to differentiate between Cu+ and Cu2+ when evaluating solubility, as they are not treated the same in this context.

PREREQUISITES
  • Understanding of solubility products and their dependence on solvent
  • Knowledge of ion charge density and hydration energy
  • Familiarity with Cu+ and Cu2+ chemical properties
  • Basic grasp of Latimer's equation
NEXT STEPS
  • Research the solubility product constant (Ksp) for CuCl2
  • Study the effects of solvent on ion solubility
  • Examine Latimer's equation for solubility dependence on ion charge and size
  • Explore hydration energy calculations for different metal ions
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Chemistry students, researchers in inorganic chemistry, and professionals involved in materials science or chemical engineering will benefit from this discussion.

Fusilli_Jerry89
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The question asks if Cu2+ is soluble with Cl- or not. I'm looking at my solubility chart and it says Cl- and Cu+ are low solubility. But I am wondering, does it matter if it is Cu+ or Cu2+? Are they both treated the same and therefore low solubile, or is just Cu+ low soluble?
 
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Can you write down the original question EXACTLY as it was given to you?

The solubility product is a strong function of the solvent - you can't speak of solubility without specifying the solvent. If unspecified, one must assume it is in water. Further, there are no absolutes in solubility (everything is soluble to some extent - that extent is defined by the solubility product).

Do you know what a solubility product is?
 
yes i do but it is not necessary in this question. I will show you a copy of the table we get.

http://www.bced.gov.bc.ca/exams/search/grade12/english/release/exam/0608CH_p.pdf

(page 24)

Notice how the table has Cu+ on it, but not Cu+2? I was just wondering if both of these ions with different combining capacities are treated as the same thing when determining whether it will be soluble or low soluble.
 
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I can't find the question there, but I do see the table.

No, you can not assume that Cu(II) will have similar solubility to Cu(I). The charge density is much higher, and hence the hydration energy is also greater, making the ion more soluble.

Look up Latimer's equation for the empirical dependence of solubility on charge and size of an ion.
 

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