Is det(A^n) equal to det(A)^n for all matrices A?

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The discussion centers on proving that det(A^n) = det(A)^n for all matrices A. The initial attempt involved using the property det(AB) = det(A)det(B) and testing it with A=B to establish that det(A^2) = det(A)^2. However, this approach is insufficient for a complete proof. The key recommendation is to utilize mathematical induction to rigorously demonstrate the equality for all integer values of n.

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Hemmer
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Question. Prove det(A^n) = det(A) ^ n

I have:

det(AB) = det(A)det(B) (holds for any number of factors)
set A=B
det(AA) = det(A)det(A)
det(A^2) = det(A)^2 ?

Is this enough for a proof?
 
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Hemmer said:
Is this enough for a proof?

Of course not, since you didn't prove what you need to prove. Hint: induction.
 

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