Is e^(2lnx) Equal to x^2?

  • Thread starter Thread starter lemurs
  • Start date Start date
  • Tags Tags
    Ln
Click For Summary
SUMMARY

The expression e^(2lnx) is definitively equal to x^2. This conclusion is derived from the property of exponents and logarithms, specifically that e^(ln(a)) = a. By applying this property, e^(2lnx) simplifies to e^(ln(x^2)), confirming that e^(2lnx) = x^2.

PREREQUISITES
  • Understanding of exponential functions
  • Knowledge of logarithmic properties
  • Familiarity with the natural logarithm (ln)
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of logarithms and exponents
  • Learn about the natural logarithm and its applications
  • Explore algebraic identities involving exponents
  • Practice simplifying expressions using logarithmic properties
USEFUL FOR

Students studying algebra, mathematics enthusiasts, and anyone looking to strengthen their understanding of logarithmic and exponential relationships.

lemurs
Messages
30
Reaction score
0
Ok really dumb one here for you but for the life of me i can't remember.

first
e^(2lnx) is that equal to x^2

like i said brain fart
thanks for the help guys
 
Physics news on Phys.org
yup, e^(2lnx) = e^(ln (x^2)) = x^2
 
e^{2\ln x}

e^{\ln{x^2}}

x^2
 

Similar threads

Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K