Is e field equal to the negative derivative of electric potential?

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Homework Help Overview

The discussion revolves around the relationship between electric field (E) and electric potential (V), specifically whether E can be considered the negative derivative of V. Participants explore the mathematical definitions and implications of this relationship in the context of vector components.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster questions the relationship between E and V, seeking clarification on whether E is indeed the negative derivative of V. Some participants elaborate on the vector nature of E and its components, while others attempt to clarify the implications of these definitions.

Discussion Status

The discussion is ongoing, with participants providing insights into the vector components of the electric field and their relationship to the electric potential. There is a recognition of the need for clarity regarding the mathematical expressions involved.

Contextual Notes

Participants are navigating the complexities of vector calculus in the context of electric fields and potentials, with some expressing confusion about the relationship as explained by their TA.

pyroknife
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Since V is the integral of -E. Shouldn't E be derivative of -V. I asked my TA that and he said something about them not having that kind of a relationship, can someone explain this?
 
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You need to sharpen your thinking. The electric field is a vector, so to specify it you need to specify its three components. These are

E_{x}=-\frac{\partial V}{\partial x}; E_{y}=-\frac{\partial V}{\partial y};E_{z}=-\frac{\partial V}{\partial z}
 
kuruman said:
You need to sharpen your thinking. The electric field is a vector, so to specify it you need to specify its three components. These are

E_{x}=-\frac{\partial V}{\partial x}; E_{y}=-\frac{\partial V}{\partial y};E_{z}=-\frac{\partial V}{\partial z}

Doesn't that just mean E is the negative derivative of V tho?
 
It means that the x component of E is the negative derivative of V with respect to x
and that the y component of E is the negative derivative of V with respect to y
and that the z component of E is the negative derivative of V with respect to z.
 
ah okay thanks
 

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