Is energy profile of a spring asymmetric with +x and -x?

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SUMMARY

The energy profile of a spring is symmetric, as described by the equation for elastic potential energy (EPE), \(E = \frac{1}{2}kx^2\). In the context of the A level physics problem, the maximum EPE occurs at the positions of 0 and 0.8, but not at 0.4, due to the specific conditions outlined in the mark scheme. The discussion clarifies that when a mass is at rest, the spring does not possess elastic potential energy, resolving the confusion regarding the energy states at various positions.

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  • Understanding of elastic potential energy and its formula, \(E = \frac{1}{2}kx^2\)
  • Basic knowledge of spring mechanics and Hooke's Law
  • Familiarity with the concepts of equilibrium and forces in physics
  • Ability to interpret mark schemes and problem statements in A level physics
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A level physics students, educators teaching mechanics, and anyone interested in understanding the principles of elastic potential energy in springs.

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Homework Statement


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The problem is with part b(ii). This is an A level question so only elementary concepts are to be used.

Homework Equations


$$E = \frac{1}{2}kx^2 $$

The Attempt at a Solution



EPE should be max at 0, 0.4, 0.8 since E is a function of $x^2$. However, mark scheme only accepts 0 and 0.8 only. It is my understanding that energy profile of a spring is symmetric under compression and expansion, but if so, why is 0.4 not acceptable?
 

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When the mass is hanging at rest as in part (a), does the spring have any elastic potential energy?
 
Ah, right, I missed that. Thanks!
 

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