- #1
Alvydas
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Lets say we have some particle A 1m above the ground.
Let it has velocity v.
Also let's consider gravitons like the reason/mechanism of the gravitation.
Let gravitons moves away from the Earth with velocity c.
Now let's consider the differences between two cases:
1 when particle A moves down and
2 when particle A moves up.
Case 1:
Particle A moves down and meets 1+v/c times more gravitons per second.
Also each graviton is stronger 1+v/c times (because of blue shift)
So the total gravitational force F = F0 * (1+v/c)^2
Case 2:
Particle A moves up and meets 1-v/c times less gravitons per second.
Also each graviton is weaker 1-v/c times (because of red shift)
So the total gravitational force F = F0 * (1-v/c)^2
What do you think?
(Please do not fetter your imagination just with one/single theory of gravity )
Let it has velocity v.
Also let's consider gravitons like the reason/mechanism of the gravitation.
Let gravitons moves away from the Earth with velocity c.
Now let's consider the differences between two cases:
1 when particle A moves down and
2 when particle A moves up.
Case 1:
Particle A moves down and meets 1+v/c times more gravitons per second.
Also each graviton is stronger 1+v/c times (because of blue shift)
So the total gravitational force F = F0 * (1+v/c)^2
Case 2:
Particle A moves up and meets 1-v/c times less gravitons per second.
Also each graviton is weaker 1-v/c times (because of red shift)
So the total gravitational force F = F0 * (1-v/c)^2
What do you think?
(Please do not fetter your imagination just with one/single theory of gravity )
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